# 2022q1 Homework 5 (quiz8)
contributed by < `Tcc0403` >
[測驗連結](https://hackmd.io/@sysprog/linux2022-quiz8)
## 測驗 1

void *memchr_opt(const void *src_void, int c, size_t length)
{
    const unsigned char *src = (const unsigned char *) src_void;
    unsigned char d = c;

    while (UNALIGNED(src)) {
        if (!length--)
            return NULL;
        if (*src == d)
            return (void *) src;
        src++;
    }

    if (!TOO_SMALL(length)) {
        /* If we get this far, we know that length is large and
         * src is word-aligned.
         */

        /* The fast code reads the source one word at a time and only performs
         * the bytewise search on word-sized segments if they contain the search
         * character, which is detected by XORing the word-sized segment with a
         * word-sized block of the search character and then detecting for the
         * presence of NULL in the result.
         */
        unsigned long *asrc = (unsigned long *) src;
        unsigned long mask = d << 8 | d;
        mask = mask << 16 | mask;
        for (unsigned int i = 32; i < LBLOCKSIZE * 8; i <<= 1)
            mask = (mask << i) | mask;

        while (length >= LBLOCKSIZE) {
            /* XXXXX: Your implementation should appear here */
	    if (DETECT_CHAR(*asrc, mask)) {
		/* Find the matching position in this block. */
		int pos = 0;
		while(pos < LBLOCKSIZE) {
		    /* Dereference the position address and compare the result
		     * with the target character. */	
		    if(*((unsigned char*) ((void *)asrc + pos++)) == d)
		        return (void *) ((void *)asrc + pos - 1);
		}
	    }
	    asrc++; // point to the next block
	    length -= LBLOCKSIZE;

        }



        /* If there are fewer than LBLOCKSIZE characters left, then we resort to
         * the bytewise loop.
         */
        src = (unsigned char *) asrc;
    }

    while (length--) {
        if (*src == d)
            return (void *) src;
        src++;
    }

    return NULL;
}

## 測驗 2

static inline ringidx_t cond_reload(ringidx_t idx, const ringidx_t *loc)
{
    ringidx_t fresh = __atomic_load_n(loc, __ATOMIC_RELAXED);
    if (before(idx, fresh)) { /* fresh is after idx, use this instead */
        idx = fresh;
    } else { /* Continue with next slot */
	/* XXXXX */ idx++;
    }
    return idx;
}

static inline ringidx_t find_tail(lfring_t *lfr, ringidx_t head, ringidx_t tail)
{
    if (lfr->flags & LFRING_FLAG_SP) /* single-producer enqueue */
        return __atomic_load_n(&lfr->tail, __ATOMIC_ACQUIRE);

    /* Multi-producer enqueue.
     * Scan ring for new elements that have been written but not released.
     */
    ringidx_t mask = lfr->mask;
    ringidx_t size = /* XXXXX */ mask + 1;

    while (before(tail, head + size) &&
           __atomic_load_n(/* XXXXX */ &lfr->tail, __ATOMIC_ACQUIRE) ==
               tail)
        tail++;
    tail = cond_update(&lfr->tail, tail);
    return tail;
}

uint32_t lfring_dequeue(lfring_t *lfr,
                        void **restrict elems,
                        uint32_t n_elems,
                        uint32_t *index)
{
    ringidx_t mask = lfr->mask;
    intptr_t actual;
    ringidx_t head = __atomic_load_n(&lfr->head, __ATOMIC_RELAXED);
    ringidx_t tail = __atomic_load_n(&lfr->tail, __ATOMIC_ACQUIRE);
    do { /* skipped */
    } while (!__atomic_compare_exchange_n(
        &lfr->head, &head, /* Updated on failure */
        /* XXXXX */ head + actual, /* New head = head + # of dequeued elements*/
        /* weak */ false, __ATOMIC_RELAXED, __ATOMIC_RELAXED));
    *index = (uint32_t) head;
    return (uint32_t) actual;
}

## 測驗 3

static void periodic_routine(struct work_struct *ws)
{
    if (likely(/* XXXXX: Implement */))
        check();
    /* XXXXX: Implement */;
}