# 145. Binary Tree Postorder Traversal
Difficulty: Medium
## Solution
```cpp=
/**
*** Author: R-CO
*** E-mail: daniel1820kobe@gmail.com
*** Date: 2020-11-10
**/
#include <cstdlib>
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
struct TreeNode {
int val;
TreeNode *left;
TreeNode *right;
TreeNode() : val(0), left(nullptr), right(nullptr) {}
TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
};
class Solution {
public:
vector<int> preorderTraversal(TreeNode* root) {
vector<int> output;
preorderTraversal(root, output);
return output;
}
private:
void preorderTraversal(TreeNode* node, vector<int> &output) {
if (node == nullptr) { return; }
output.push_back(node->val);
preorderTraversal(node->left, output);
preorderTraversal(node->right, output);
}
};
int main(int argc, char *argv[]) { return EXIT_SUCCESS; }
```
## Result
Success
Details
Runtime: 0 ms, faster than 100.00% of C++ online submissions for Binary Tree Preorder Traversal.
Memory Usage: 8.9 MB, less than 5.36% of C++ online submissions for Binary Tree Preorder Traversal.
###### tags: `LeetCode-Medium` `C++`