# 145. Binary Tree Postorder Traversal Difficulty: Medium ## Solution ```cpp= /** *** Author: R-CO *** E-mail: daniel1820kobe@gmail.com *** Date: 2020-11-10 **/ #include <cstdlib> /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode() : val(0), left(nullptr), right(nullptr) {} * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} * }; */ struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode() : val(0), left(nullptr), right(nullptr) {} TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} }; class Solution { public: vector<int> preorderTraversal(TreeNode* root) { vector<int> output; preorderTraversal(root, output); return output; } private: void preorderTraversal(TreeNode* node, vector<int> &output) { if (node == nullptr) { return; } output.push_back(node->val); preorderTraversal(node->left, output); preorderTraversal(node->right, output); } }; int main(int argc, char *argv[]) { return EXIT_SUCCESS; } ``` ## Result Success Details Runtime: 0 ms, faster than 100.00% of C++ online submissions for Binary Tree Preorder Traversal. Memory Usage: 8.9 MB, less than 5.36% of C++ online submissions for Binary Tree Preorder Traversal. ###### tags: `LeetCode-Medium` `C++`