---
tags: AC LeetCode 刷題讀書會 - 2023
---

# 2023/04/23(日) 每週 LeetCode 刷題

## 刷題題號
- [1929. Concatenation of Array](https://leetcode.com/problems/concatenation-of-array/)

## 解題思路
1. 給予一個整數陣列 nums 和長度為 n，你想新增一個長度為 2n 的陣列 ans。
其中 ans[i] == nums[i] and ans[i + n] == nums[i] for 0 <= i < n (0-indexed).
具體來說，ans 是兩次 nums 陣列的串聯，回傳 ans 的陣列。

## 回報格式

- 請 Fork 此 Replit 連結(https://replit.com/@AllenLi23/AC-LeetCode-Js-1480-Running-Sum-of-1d-Array)後，進行程式碼解題，並於完成後更新到 Replit 中，再將連結貼至「解題分享區」來與大家交流做法。

解題分享區
---
2023/04/23 讀書會議流程：

ex. 09:05開始

#簽到表：
https://docs.google.com/spreadsheets/d/1gc16rrF-yZNs845z_nYrdgDIiSECOJok30dNLyQm69A/edit#gid=0

1. 題目說明。
2. 題目解析(BigO(2n) => BigO(n))。
4. 成員分享解題思路。
5. 問題與討論。

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Replit：https://replit.com/@AllenLi23/AC-LeetCode-Js-1929-Concatenation-of-Array-Allen
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name: Jack Hung
lighthouse: [e-mail]
Replit：https://replit.com/@LungHsuanHung/AC-LeetCode-Go-1929-Concatenation-of-Array#main.go
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Replit：https://replit.com/@chloewithcheese/AC-LeetCode-Js-1929-Concatenation-of-Array#index.js
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Replit: https://replit.com/@Beginneraboutli/AC-LeetCode-Js-1929-Concatenation-of-Array
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Replit：https://replit.com/@vanessalin3/AC-LeetCode-Js-1929-Concatenation-of-Array#index.js
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Replit：https://replit.com/@Shu-YinChen/AC-LeetCode-Js-1929-Concatenation-of-Array#index.js
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Replit：https://replit.com/@Robert83213/AC-LeetCode-Js-1929-Concatenation-of-Array#index.js
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lighthouse: [e-mail]
Replit：https://replit.com/@ggg1237890/AC-LeetCode-Js-1929-Concatenation-of-Array#index.js
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name: Anna Chu
lighthouse: [e-mail]
Replit：https://replit.com/@AnnaChu1/AC-LeetCode-Js-1929-Concatenation-of-Array#index.js
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name: Henry
lighthouse: [e-mail]
Replit：https://replit.com/@Chi-HengChen/AC-LeetCode-Js-1929-Concatenation-of-Array#index.js
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lighthouse: [e-mail]
Replit：https://replit.com/@a84012807/AC-LeetCode-Js-1929-Concatenation-of-Array?s=app
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Replit：https://replit.com/@yongsin0129/AC-LeetCode-Js-1929-Concatenation-of-Array#index.js
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Replit：https://replit.com/@Ke-en/AC-LeetCode-Js-1929-Concatenation-of-Array#index.js
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