---
# System prepended metadata

title: 2023/08/13(日) 每週 LeetCode 刷題
tags: [AC LeetCode 刷題讀書會 - 2023]

---

---
tags: AC LeetCode 刷題讀書會 - 2023
---

#  2023/08/13(日) 每週 LeetCode 刷題

## 刷題題號
-  [58. Length of Last Word](https://leetcode.com/problems/length-of-last-word/)

## 解題思路
Given a string s consisting of words and spaces, return the length of the last word in the string.
A word is a maximal substring consisting of non-space characters only.
<pre style='background-color:#ggg'>
給予一個字串 s 是由字母與空白所組成，回傳最後一個字母的字串長度。
單一個字母是僅由非空格字符組成的最大字串。
</pre>


## 回報格式

- 請 Fork 此 Replit 連結(https://replit.com/@AllenLi23/AC-LeetCode-Js-58-Length-of-Last-Word)後，進行程式碼解題，並於完成後更新到 Replit 中，再將連結貼至「解題分享區」來與大家交流做法。

解題分享區
---

讀書會議流程：

ex. 21:05開始 

#簽到表：
https://docs.google.com/spreadsheets/d/1gc16rrF-yZNs845z_nYrdgDIiSECOJok30dNLyQm69A/edit#gid=534323210

1. 題目說明。
2. 題目解析(BigO(n))。
4. 成員分享解題思路。
5. 問題與討論。


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name: name (回報範例)
lighthouse: lighthouse
Replit：https://replit.com/@AllenLi23/AC-LeetCode-Js-58-Length-of-Last-Word-Allen
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lighthouse: lhhungx@gmail.com
Replit：https://replit.com/@LungHsuanHung/AC-LeetCode-Go-58-Length-of-Last-Word#solution/solution.go
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Replit：https://replit.com/@peggy8865/AC-LeetCode-Js-58-Length-of-Last-Word#index.js
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lighthouse: pythonforeye@gmail.com
Replit: https://replit.com/@Beginneraboutli/AC-LeetCode-Js-58-Length-of-Last-Word#index.js
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lighthouse: bun.coding@gmail.com
Replit: https://replit.com/@Shu-YinChen/AC-LeetCode-Js-58-Length-of-Last-Word#index.js
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name: 小波
lighthouse: sean821125@gmail.com
Replit: https://replit.com/@sean821125/AC-LeetCode-Js-58-Length-of-Last-Word#index.js
-->

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name: Ben
lighthouse: a84012807@gmail.com
Replit: https://replit.com/@a84012807/AC-LeetCode-Js-58-Length-of-Last-Word#index.js
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