--- tags: AC LeetCode 刷題讀書會 - 2023 --- # 2023/08/13(日) 每週 LeetCode 刷題 ## 刷題題號 - [58. Length of Last Word](https://leetcode.com/problems/length-of-last-word/) ## 解題思路 Given a string s consisting of words and spaces, return the length of the last word in the string. A word is a maximal substring consisting of non-space characters only. <pre style='background-color:#ggg'> 給予一個字串 s 是由字母與空白所組成,回傳最後一個字母的字串長度。 單一個字母是僅由非空格字符組成的最大字串。 </pre> ## 回報格式 - 請 Fork 此 Replit 連結(https://replit.com/@AllenLi23/AC-LeetCode-Js-58-Length-of-Last-Word)後,進行程式碼解題,並於完成後更新到 Replit 中,再將連結貼至「解題分享區」來與大家交流做法。 解題分享區 --- 讀書會議流程: ex. 21:05開始 #簽到表: https://docs.google.com/spreadsheets/d/1gc16rrF-yZNs845z_nYrdgDIiSECOJok30dNLyQm69A/edit#gid=534323210 1. 題目說明。 2. 題目解析(BigO(n))。 4. 成員分享解題思路。 5. 問題與討論。 <!-- No.0 (請依序排序下去) name: name (回報範例) lighthouse: lighthouse Replit:https://replit.com/@AllenLi23/AC-LeetCode-Js-58-Length-of-Last-Word-Allen --> <!-- No.1 name: Jack Hung lighthouse: lhhungx@gmail.com Replit:https://replit.com/@LungHsuanHung/AC-LeetCode-Go-58-Length-of-Last-Word#solution/solution.go --> <!-- No.2 name: Peggy lighthouse: peggy8865@gmail.com Replit:https://replit.com/@peggy8865/AC-LeetCode-Js-58-Length-of-Last-Word#index.js --> <!-- No.3 name: Kai lighthouse: pythonforeye@gmail.com Replit: https://replit.com/@Beginneraboutli/AC-LeetCode-Js-58-Length-of-Last-Word#index.js --> <!-- No.4 name: Bun lighthouse: bun.coding@gmail.com Replit: https://replit.com/@Shu-YinChen/AC-LeetCode-Js-58-Length-of-Last-Word#index.js --> <!-- No.5 name: 小波 lighthouse: sean821125@gmail.com Replit: https://replit.com/@sean821125/AC-LeetCode-Js-58-Length-of-Last-Word#index.js --> <!-- No.6 name: Ben lighthouse: a84012807@gmail.com Replit: https://replit.com/@a84012807/AC-LeetCode-Js-58-Length-of-Last-Word#index.js -->