###### tags: Python
# Function

DRY = Donot repeat yourself
Should do one thing really well.
Should return something.

## Parameters

def say_hello(name, emoji):
    print(f'helllooo {name}{emoji}')

## Positional arguments

say_hello('Andrei', ':)')

## Keyword arguments

say_hello(emoji=':)', name='Bibi')

## Default parameters

def say_hello(name='Darth Vader', emoji='@@')
    print(f'helllooo {name}{emoji}')

## Return

def sum(num1, num2):
   return num1 + num2

def sum(num1, num2):
    def another_func(n1, n2):
        return n1 + n2
    return another_func(num1, num2)

## Docstring

def teas(a):
    '''
    Info: this function tests and prints param a
    '''
    print(a)

help(test)
print(test.__doc__)

## Clean code

def is_even(num):
    if num % 2 == 0:
        return True
    elif num % 2 != 0:
        return False

neater

def is_even(num):
    if num % 2 == 0:
        return True
    else:
        return False

neater

def is_even(num):
    if num % 2 == 0:
        return True
    return False

neater

def is_even(num):
    return num % 2 == 0

## Arguments / Keyword arguments

Rule: params, *args, default paramters, **kwargs
def super_func(name, *args, 'hi', **kwargs)
### *args = arguments

def super_func(*args):
    print(args) - type:tupple
    returm sum(args)

### *kwargs = keyword arguments

def super_func(*args, **kwargs):
    total = 0
    for items in kwargs.values():
        total += items
    returm sum(args) + total
print(super_func(1,2,3,4,5, num1=5, num2=10))

output:30

# Method
be owned by something
ex: 'hello'.capitalize()

# Scope - what variables do I have access to?

#1 - start with local scope
#2 - parent local scope
#3 - global
#4 - built-in python functions

a = 1

def parent():
    a = 10
    def confusion():
        return a
    return confusion()

print(confusion())
print(a)

## non local

def outer():
    x = 'local'
    def inner():
        nonlocal x
        x = 'nonlocal'
        print('inner:', x)
        
    inner()
    print('outer:', x)