---
# System prepended metadata

title: Handout Fill In (Introduction of Computer Science)
tags: [必修, Introduction of Computer Sciencce, NTNU, CSIE]

---

# Handout Fill In (Introduction of Computer Science)

##### [Back to Introduction of Computer Science](https://reurl.cc/XXeYaE)

###### tags: `NTNU` `CSIE` `必修`  `Introduction of Computer Sciencce` 
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## Ch1 Fill In (All)

Ch1-14  Addition and subtraction

Ch1-15  multiplication and division as well as addition and subtraction 

Ch1-16  punched card

Ch1-17  polynomial[^polynomial]

Ch1-19  tabulating[^tabulating]，tally[^tally]and sort data stored on punched cards

Ch1-24  input data

Ch1-28  linear equations

Ch1-29  general-purpose electronic computer （程式為外接式，可換）

Ch1-32  memory,binary patterns（模式）

Ch1-33  EDVAC

Ch1-38  Central Processing

Ch1-41  十八個月

Ch1-47  Algorithms,Operating Systems



[^polynomial]: polynomial：多項式
[^tabulating]: tabulating：製表
[^tally]: tally：匯集

## Ch2 Fill In (All)

Ch2-1　**印度人**發明阿拉伯數字

Ch2-2　(2A)~16~ = **(52)~8~** = (42)~10~, **non-positional** systems

Ch2-3　**base**[^base]=radix 

Ch2-4　b=**10**   ,    **powers** of 10 

Ch2-5　**minus**

Ch2-6　**integral** part[^integral_part]+fraction part[^Fraction_part]

Ch2-7　**Roman**

Ch2-8　bits=binary **digits**,**base**,**decimal**

Ch2-10　**fractional** part, **5.75**

Ch2-11　b=**8**

Ch2-13　b=**16**

Ch2-15　**decimal**[^decimal] point

Ch2-17　Divide X continuously by **b**

Ch2-18　Q:Quotients[^quotient] R:**Remainders**[^remainder], **0**

Ch2-19　quotient is **0**? Quotient becomes new **source**

Ch2-20　**(7E)**~16~

Ch2-21　convert the **Fractional** part to binary

Ch2-22　Multiply source by **base** to get a result

Fraction part of result becomes new **source**

Fraction part is zero or **destination** digits [^destination_digits]are enough?

Ch2-23　**rounded**

Ch2-25　**16**

Ch2-26　**E**

Ch2-27　**6**

Ch2-28　(**4E2**)~16~

Ch2-29　**E**

Ch2-31　**X**
[^base]:base：底數
[^integral_part]:integral_part：整數
[^Fraction_part]:fraction_part：小數
[^decimal]:decimal：十進位
[^quotient]:quotient：商
[^remainder]:remainder：餘
[^destination_digits]:destination_digits：指定的小數位數

## Ch3 Fill In (部分有缺)
Ch3-3 **byte**

Ch3-4 **11111000**

Ch3-6 **65535**

Ch3-11 **10000000**

Ch3-12 **51F**

Ch3-13 **00000111**

Ch3-14 **1111111011111101**

Ch3-15 **twice**

Ch3-16 **2^n-1^-1**

Ch3-17 **76544**

Ch3-18 **twice**

Ch3-20 **32767**

Ch3-22 **01100110**

Ch3-26　The sign is negative, so S = **1**

Ch3-27　The number is **-2104387.8**

Ch3-28　**lowercase**

Ch3-29　**16**

Ch3-30　**$2^7$**

Ch3-31　**parity** check

Ch3-32　**$8$**

Ch3-33　**2**

Ch3-34　**127**

Ch3-37　**1000**

Ch3-39　**256**

Ch3-40　**65536**

Ch3-41　**1677**

Ch3-46　Postscript font以 **4** 個點表示一個曲線

## Ch4 Fill in (All)

ch4-2　**unary** 

ch4-4　**01100111**

ch4-5　both inputs are **1**

ch4-7　both inputs are **0**

ch4-9　both inputs are the **same**

ch4-10　奇數個1，結果為**1**
      　偶數個1，結果為**0**

ch4-13　Result **11111110**　

ch4-14　Result **01011110**

ch4-17　a << 2 = **10010100**

ch4-20　b >> 1 = **-5**(arithmetic shift的結果不同於整數除法)

ch4-24　**00000111**

ch4-27　**00100111**

ch4-30　6 + **127**
<!---->

## Ch5
### 10/17

Ch5-2  每秒**30億次**運算

Ch5-5 **Instruction registers**

Ch5-6 A simplified cycle can consist of three steps: fetch,**decode**,

Ch5-9 Tera = 2^40^

Ch5-10 nm = 奈米

Ch5-11 RAM:Random **Access** Memory
      DRAM:**Dynamic** Ramdom Acess Memory 
      
Ch5-12 ROM:**Read** Only Memory

### 10/21

Ch5-15 記得把第三項"而蓄意省略不重要的    20%"中的"20%"改為**80%** 

### 10/28

Ch5-39 3.**Excute**








