Implement pow(x, n), which calculates x
raised to the power n
(i.e., xn).
Example 1:
Input: x = 2.00000, n = 10
Output: 1024.00000
Example 2:
Input: x = 2.10000, n = 3
Output: 9.26100
Example 3:
Input: x = 2.00000, n = -2
Output: 0.25000
Explanation: 2-2 = 1/22 = 1/4 = 0.25
Constraints:
x
< 100.0n
<= 231-1n
is an integer.x
is not zero or n > 0
.
function myPow(x, n) {
let result = 1;
while (n) {
if (n % 2) {
if (n > 0) {
result *= x;
} else {
result /= x;
}
}
x = x * x;
n = ~~(n / 2);
}
return result;
}
MarsgoatJul 24, 2023
class Solution {
public:
double myPow(double base, int n) {
long long exponent = (long long) n;
if (exponent == 0) {
return 1;
}
if (exponent < 0) {
base = 1 / base;
exponent = -exponent;
}
double ans = 1;
while (exponent > 0) {
if (exponent % 2 == 1) {
ans *= base;
exponent -= 1;
}
base = base * base;
exponent /= 2;
}
return ans;
}
template<typename T>
void printVector(const vector<T>& vec) {
for (const T& element : vec) {
cout << element << ",";
}
cout << endl;
}
};
Jerry Wu24 July, 2023