<style> html, body, .ui-content { background: #222222; color: #00BFFF; } ::-webkit-scrollbar { width: 10px; } ::-webkit-scrollbar-track { background: transparent; } ::-webkit-scrollbar-thumb { background: linear-gradient(180deg, #2BE8CF60 0%, #2B83E860 100%); border-radius: 3px; } ::-webkit-scrollbar-thumb:hover { background: linear-gradient(180deg, #2BE8CF95 0%, #2B83E895 100%); } /* 設定 code 模板 */ .markdown-body code, .markdown-body tt { background-color: #ffffff36; } .markdown-body .highlight pre, .markdown-body pre { color: #ddd; background-color: #00000036; } .hljs-tag { color: #ddd; } .token.operator { background-color: transparent; } </style> ###### tags: `Leetcode` # 2616. Minimize the Maximum Difference of Pairs ## 題目 ###### Link : https://leetcode.com/problems/minimize-the-maximum-difference-of-pairs/ ## 程式碼 ```cpp= class Solution { public: bool check(vector<int>& nums, int mid, int& p){ int count = 0, n = nums.size(); for(int i = 0;i < n - 1 && count < p;){ if(nums[i + 1] - nums[i] <= mid){ ++count; i += 2; } else ++i; } return count >= p; } int minimizeMax(vector<int>& nums, int p) { sort(nums.begin(), nums.end()); int left = 0, right = nums.back() - nums[0]; while(left <= right){ int mid = (left + right) / 2; if(check(nums, mid, p)){ right = mid - 1; } else{ left = mid + 1; } } return left; } }; ```