---
# System prepended metadata

title: 226. Invert Binary Tree
tags: [Leetcode]

---

<style>
    html, body, .ui-content {
    background: #222222;
    color: #00BFFF;
}
::-webkit-scrollbar {
    width: 10px;
}
::-webkit-scrollbar-track {
    background: transparent;
}
::-webkit-scrollbar-thumb {
    background: linear-gradient(180deg, #2BE8CF60 0%, #2B83E860 100%);
    border-radius: 3px;
}
::-webkit-scrollbar-thumb:hover {
    background: linear-gradient(180deg, #2BE8CF95 0%, #2B83E895 100%);
}
    /* 設定 code 模板 */
    .markdown-body code,
.markdown-body tt {
    background-color: #ffffff36;
}
.markdown-body .highlight pre,
.markdown-body pre {
    color: #ddd;
    background-color: #00000036;
}
.hljs-tag {
    color: #ddd;
}
.token.operator {
  background-color: transparent;
}
   
</style>

###### tags: `Leetcode`

# 226. Invert Binary Tree


###### Link : https://leetcode.com/problems/invert-binary-tree/description/

## 題目
將整棵樹變成鏡像的
## 程式碼

```cpp=
/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
    TreeNode* invertTree(TreeNode* root) {
        Swap(root);
        return root;
    }
    void Swap(TreeNode* node){
        if(!node) return;
        Swap(node->left);
        Swap(node->right);
        swap(node->left, node->right);
        return;
    }
};
```