# 參考答案

## 五則運算

a = input("請輸入兩位數：")
b = input("請輸入一位數：")
a = eval(a)
b = eval(b)

print("%d + %d = %4d" % (a , b , a+b))
print("%d - %d = %4d" % (a , b , a-b))
print("%d * %d = %4d" % (a , b , a*b))
print("%d / %d = %7.2f" % (a , b , a/b))
print("%d" % (a),"%" ,"%d = %4d" % (b , a%b),"\n")

print( "%d = %d * %d + %d" %(a , b , a//b ,a%b))

## 文文的求婚

year = eval(input())
    if (year % 4 == 0 ):
        if (year % 400 == 0):
            print('閏年')
        elif (year % 100 == 0):
            print('平年')
        else:
            print('閏年')
    else:
        print('平年')        

## 肥宅快樂水

m = input("請輸入一個金額：")
m = eval(m)
a = m // 17
b = a #空瓶數
c = a #瓶蓋數
d = 0 #兌換瓶數

while (b >= 3 or c >= 5 or d > 0):

    d =  b // 3 + c // 5 #計算本次可再兌換數
    b = b % 3 #更新成兌換後數目
    c = c % 5 
    
    if (d == 0 and b == 2 and c >= 3): #建立特殊情境(當可兌換一瓶時，可用3瓶蓋彌補1空瓶的缺額)
        b = b + 1 #補缺
        c = c - 3 #扣除
        d = b // 3 #更新成正確可再兌換數
        b = b % 3 
    
    if (d > 0):
        print("   喝了%3d瓶可樂，可再換%3d瓶，剩下%2d罐空瓶和%2d個瓶蓋。" % (a,d,b,c))
        
    b = b + d #加入兌換數額
    c = c + d 
    a = a + d
    
print("總共喝了%3d瓶可樂，剩下%2d罐空瓶%2d個瓶蓋和%2d元。" % (a,b,c,m%17))