matlab 作業 工科系111級 林洵 E94076063 # **作業1** ``` m = 1; M = 5; L = 2; g = -10; d = 1; s = 1; % pendulum up (s=1) A = [0 1 0 0; 0 -d/M -m*g/M 0; 0 0 0 1; 0 -s*d/(M*L) -s*(m+M)*g/(M*L) 0]; B = [0; 1/M; 0; s*1/(M*L)]; Q = [1 0 0 0; 0 30 0 0; 0 0 10 0; 0 0 0 10]; R = .0001; %% det(ctrb(A,B)) %% K = lqr(A,B,Q,R); tspan = 0:.001:15; if(s==-1) y0 = [0; 0; 0; 0]; [t,y] = ode45(@(t,y)cartpend(y,m,M,L,g,d,-K*(y-[4; 0; 0; 0])),tspan,y0); elseif(s==1) y0 = [-3; 0; pi+.45; 0]; % % [t,y] = ode45(@(t,y)((A-B*K)*(y-[0; 0; pi; 0])),tspan,y0); [t,y] = ode45(@(t,y)cartpend(y,m,M,L,g,d,-K*(y-[1; 0; pi; 0])),tspan,y0); else end for k=1:100:length(t) drawcartpend_bw(y(k,:),m,M,L); end % function dy = pendcart(y,m,M,L,g,d,u) ``` # 作業2 code部分 ``` title('step response with digital lqr control') x=y(:,1); x_dot=y(:,2); theta=y(:,3); theta_dot=y(:,4); subplot(4, 1, 1); plot(t, x); xlabel('time') ylabel('x') grid on hold on subplot(4, 1, 2); plot(t, x_dot); xlabel('time') ylabel('x dot') grid on hold on subplot(4, 1, 3); plot(t, theta); xlabel('time') ylabel('theta') grid on hold on subplot(4, 1, 4); plot(t, theta_dot); xlabel('time') ylabel('theta dot') grid on hold on ``` 圖表呈現 ![](https://i.imgur.com/28GZPNB.png) # 作業3 # code部分 ``` y0 = [-3; 0; pi+.5; 0]; x_dis_1=-1; for a=1:1:length(t) x_dis = y(a,1); if x_dis_1 > x_dis x_dis_1 = x_dis; a_time = a/1000; end end dx_dis_1 = -1; for a = 1:1:length(t) dx_dis = y(a,2); if dx_dis_1 > dx_dis dx_dis_1 = dx_dis; end end angle =0; balance_time =0; for a = 1:1:length(t) angle_1 = abs(y(a,3)-(pi)); angle_2 = angle_1*(180/pi); if angle_2 > 1 balance_time =t(a); end if angle < angle_1 angle = angle_1; end end dtheta_dis_2 = -1; for a = 1:1:length(t) dtheta_dis = y(a,4); if dtheta_dis < dtheta_dis_2 dtheta_dis_2 = dtheta_dis; end end x_dis_1 dx_dis_1 balance_time angle_2 ``` 結果 ![](https://i.imgur.com/md14VRP.png) X的距離:-4.8301 速度:-5.6199 平衡時間:2.0831 角度:0.0902