###### tags: `LeetCode`,`Python3`,`Easy`
# 231. Power of Two
### **題目連結：** [**Power of Two**](https://leetcode.com/problems/power-of-two/description/?envType=daily-question&envId=2024-02-19)

### **解題方向**
* 判斷某數是不是2的指數，只要一直將該值除2即可，最終如果是1的話就代表是
### **完整程式碼**

class Solution:
    def isPowerOfTwo(self, n: int) -> bool:
        if n==0 :return False
        while n%2==0:n/=2
        return n==1