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# CHAPTER 2 Problem 117

<span class="room-tag">From January 26, 1977, to September 18, 1983, George Meegan of Great Britain walked from Ushuaia, at the southern tip of South America, to Prudhoe Bay in Alaska, covering 30,600 km. In meters per second, what was the magnitude of his average velocity during that time period?</span>

<br/>

根據平均速率之定義：
\begin{aligned}
\bar{v} ={{\ell } \over {\Delta t}}
\end{aligned}
<br>

$\ell$為路徑長，其值為30600km，步行時間(Walking time)為2426天，
\begin{aligned}
\bar{v} ={{\ell } \over {\Delta t}}=\frac{30600\ \mathrm{km}}{2426\ \mathrm{day}}=\frac{30600\times 1000\ \mathrm{m}}{2426 \times \ 86400\ \mathrm{s}} \approx 0.15\ (\mathrm{m/s})
\end{aligned}
<br>

###### tag: `Fundamentals of Physics`