--- tags: HW5.2 --- # ***Computational Hydraulics*** ## **Group 01:** N88071053 洪豪男 N88091011 黃彥鈞 ## **HW5.2:** Please prove the above formulation --- $u^{n+1}_j = \lambda a^n_{j-1/2}w^{n+1}_{j-1/2} +\Bigl[1 - \lambda\left(a^n_{j-1/2}+a^n_{j+1/2}\right)\Bigr]w^{n+1}_j \\ \quad\quad\quad+\lambda a^n_{j+1/2}w^{n+1}_{j+1/2}+ \dfrac{\Delta x}{2}\Bigl[(\lambda a^n_{j-1/2})^2(u_x)^{n+1}_{j-1/2}-(\lambda a^n_{j+1/2})^2(u_x)^{n+1}_{j+1/2}\Bigr]$ $\dfrac{u^{n+1}_j - u^n_j}{\Delta t}=\dfrac{1}{\Delta x} a^n_{j-1/2}w^{n+1}_{j-1/2} +\Bigl[\dfrac{1}{\Delta t} - \dfrac{(a^n_{j-1/2}+a^n_{j+1/2})}{\Delta x}\Bigr]w^{n+1}_j \\ \quad\quad\quad\quad\quad+\dfrac{1}{\Delta x} a^n_{j+1/2}w^{n+1}_{j+1/2}- \dfrac{1}{\Delta t}u_j^n+{\cal O}(\lambda)$ --- $\begin{array}{rl}w_{j-1/2}^{n+1}=&\dfrac{u_j^n+u_{j-1}^n}{2}+ \dfrac{\Delta x - a^{n}_{j-1/2}\Delta t}{4}\Bigl[(u_x)^{n}_{j-1}-(u_x)^{n}_{j}\Bigr]\\ &-\dfrac{1}{2a_{j-1/2}^{n}}\Bigl[f\bigl(u^{n+1/2}_{j-1/2,r}\bigr)- f\bigl(u^{n+1/2}_{j-1/2,l}\bigr)\Bigr] \end{array}$ $\dfrac{1}{\Delta x} a^n_{j-1/2}w^{n+1}_{j-1/2} \\=\dfrac{a^n_{j-1/2}}{2 \Delta x}(u_j^n+u_{j-1}^n)+ \dfrac{a^{n}_{j-1/2}}{4}\Bigl[(u_x)^{n}_{j-1}-(u_x)^{n}_{j}\Bigr]-\dfrac{\lambda (a^{n}_{j-1/2})^2}{4}\Bigl[(u_x)^{n}_{j-1}-(u_x)^{n}_{j}\Bigr] \\\quad-\dfrac{1}{2 \Delta x}\Bigl[f\bigl(u^{n+1/2}_{j-1/2,r}\bigr)- f\bigl(u^{n+1/2}_{j-1/2,l}\bigr)\Bigr]$ --- $w_{j}^{n+1}=u^n_j+\dfrac{\Delta t}{2}(a^n_{j-1/2}-a^n_{j+1/2})(u_x)^{n}_{j} \\\quad\quad-\dfrac{\lambda}{1 -\lambda(a^n_{j+1/2}+a^n_{j-1/2})}[f\bigl(u^{n+1/2}_{j+1/2,l}\bigr) - f\bigl(u^{n+1/2}_{j-1/2,r}\bigr)\Bigr]$ $\Bigl[\dfrac{1}{\Delta t} - \dfrac{(a^n_{j-1/2}+a^n_{j+1/2})}{\Delta x}\Bigr]w^{n+1}_j \\=\dfrac{1}{\Delta t}u^n_j-\dfrac{(a^n_{j-1/2}+a^n_{j+1/2})}{\Delta x}u^n_j+\dfrac{1}{2}(a^n_{j-1/2}-a^n_{j+1/2})(u_x)^{n}_{j} \\\quad-\dfrac{\lambda}{2}(a^n_{j-1/2}-a^n_{j+1/2})(a^n_{j-1/2}+a^n_{j+1/2})(u_x)^{n}_{j}-\dfrac{1}{\Delta x}[f\bigl(u^{n+1/2}_{j+1/2,l}\bigr) - f\bigl(u^{n+1/2}_{j-1/2,r}\bigr)\Bigr]$ --- $\begin{array}{rl}w_{j+1/2}^{n+1}=&\dfrac{u_j^n+u_{j+1}^n}{2}+ \dfrac{\Delta x - a^{n}_{j+1/2}\Delta t}{4}\Bigl[(u_x)^{n}_{j}-(u_x)^{n}_{j+1}\Bigr]\\ &-\dfrac{1}{2a_{j+1/2}^{n}}\Bigl[f\bigl(u^{n+1/2}_{j+1/2,r}\bigr)- f\bigl(u^{n+1/2}_{j+1/2,l}\bigr)\Bigr] \end{array}$ $\dfrac{1}{\Delta x} a^n_{j+1/2}w^{n+1}_{j+1/2} \\=\dfrac{a^n_{j+1/2}}{2 \Delta x}(u_j^n+u_{j+1}^n)+ \dfrac{a^{n}_{j+1/2}}{4}\Bigl[(u_x)^{n}_{j}-(u_x)^{n}_{j+1}\Bigr]-\dfrac{\lambda (a^{n}_{j-1/2})^2}{4}\Bigl[(u_x)^{n}_{j}-(u_x)^{n}_{j+1}\Bigr] \\\quad-\dfrac{1}{2 \Delta x}\Bigl[f\bigl(u^{n+1/2}_{j+1/2,r}\bigr)- f\bigl(u^{n+1/2}_{j+1/2,l}\bigr)\Bigr]$ --- $\dfrac{u^{n+1}_j - u^n_j}{\Delta t}$ \= $\Biggl\{\dfrac{a^n_{j-1/2}}{2 \Delta x}(u_j^n+u_{j-1}^n)+\dfrac{a^{n}_{j-1/2}}{4}\Bigl[(u_x)^{n}_{j-1}-(u_x)^{n}_{j}\Bigr]$ $\quad-\dfrac{\lambda (a^{n}_{j-1/2})^2}{4}\Bigl[(u_x)^{n}_{j-1}-(u_x)^{n}_{j}\Bigr] \\\quad-\dfrac{1}{2 \Delta x}\Bigl[f\bigl(u^{n+1/2}_{j-1/2,r}\bigr)-f\bigl(u^{n+1/2}_{j-1/2,l}\bigr)\Bigr]\Biggr\} \\\quad+ \Biggl\{\dfrac{1}{\Delta t}u^n_j-\dfrac{(a^n_{j-1/2}+a^n_{j+1/2})}{\Delta x}u^n_j+\dfrac{1}{2}(a^n_{j-1/2}-a^n_{j+1/2})(u_x)^{n}_{j} \\\quad-\dfrac{\lambda}{2}(a^n_{j-1/2}-a^n_{j+1/2})(a^n_{j-1/2}+a^n_{j+1/2})(u_x)^{n}_{j} -\dfrac{1}{\Delta x}[f\bigl(u^{n+1/2}_{j+1/2,l}\bigr) - f\bigl(u^{n+1/2}_{j-1/2,r}\bigr)\Bigr]\Biggr\} \\\quad+\Biggl\{\dfrac{a^n_{j+1/2}}{2 \Delta x}(u_j^n+u_{j+1}^n)+ \dfrac{a^{n}_{j+1/2}}{4}\Bigl[(u_x)^{n}_{j}-(u_x)^{n}_{j+1}\Bigr]-\dfrac{\lambda (a^{n}_{j-1/2})^2}{4}\Bigl[(u_x)^{n}_{j}-(u_x)^{n}_{j+1}\Bigr] \\\quad-\dfrac{1}{2 \Delta x}\Bigl[f\bigl(u^{n+1/2}_{j+1/2,r}\bigr)- f\bigl(u^{n+1/2}_{j+1/2,l}\bigr)\Bigr]\Biggr\}- \dfrac{1}{\Delta t}u_j^n+{\cal O}(\lambda) \\= \Biggl\{\dfrac{a^n_{j-1/2}}{2 \Delta x}(u_j^n+u_{j-1}^n)+ \dfrac{a^{n}_{j-1/2}}{4}\Bigl[(u_x)^{n}_{j-1}-(u_x)^{n}_{j}\Bigr]-\dfrac{1}{2 \Delta x}\Bigl[f\bigl(u^{n+1/2}_{j-1/2,r}\bigr)- f\bigl(u^{n+1/2}_{j-1/2,l}\bigr)\Bigr] \\\quad-\dfrac{(a^n_{j-1/2}+a^n_{j+1/2})}{\Delta x}u^n_j+\dfrac{1}{2}(a^n_{j-1/2}-a^n_{j+1/2})(u_x)^{n}_{j}-\dfrac{1}{2\Delta x}[2f\bigl(u^{n+1/2}_{j+1/2,l}\bigr) - 2f\bigl(u^{n+1/2}_{j-1/2,r}\bigr)\Bigr] \\\quad+\dfrac{a^n_{j+1/2}}{2 \Delta x}(u_j^n+u_{j+1}^n)+ \dfrac{a^{n}_{j+1/2}}{4}\Bigl[(u_x)^{n}_{j}-(u_x)^{n}_{j+1}\Bigr]-\dfrac{1}{2 \Delta x}\Bigl[f\bigl(u^{n+1/2}_{j+1/2,r}\bigr)- f\bigl(u^{n+1/2}_{j+1/2,l}\bigr)\Bigr]\Biggr\} \\\quad+\Biggl\{\dfrac{\lambda (a^{n}_{j-1/2})^2}{4}\Bigl[(u_x)^{n}_{j}-(u_x)^{n}_{j-1}\Bigr]-\dfrac{\lambda (a^{n}_{j-1/2})^2}{4}\Bigl[(u_x)^{n}_{j}-(u_x)^{n}_{j+1}\Bigr]\Biggr\}+\Biggl\{\dfrac{1}{\Delta t}u^n_j-\dfrac{1}{\Delta t}u^n_j\Biggr\} \\\quad-\Biggl\{\dfrac{\lambda}{2}(a^n_{j-1/2}-a^n_{j+1/2})(a^n_{j-1/2}+a^n_{j+1/2})(u_x)^{n}_{j}+{\cal O}(\lambda)\Biggr\} \\=\dfrac{1}{2\Delta x}\Biggl\{-\Bigl[\left(f\left(u^{n+1/2}_{j+1/2,r}\right)+f\left(u^{n+1/2}_{j+1/2,l}\right)\right)-\left(f\left(u^{n+1/2}_{j-1/2,r}\right)+f\left(u^{n+1/2}_{j-1/2,l}\right)\right)\Bigr]\Biggr.\\ \quad \left.+a^n_{j+1/2}\left[\left(u^n_{j+1}-\dfrac{\Delta x}{2}(u_x)^n_{j+1}\right)-\left(u^n_{j}+\dfrac{\Delta x}{2}(u_x)^n_j\right)\right]\right.\\ \quad \Biggl.-a^n_{j-1/2}\left[\left(u^n_{j}-\dfrac{\Delta x}{2}(u_x)^n_{j}\right)-\left(u^n_{j-1}+\dfrac{\Delta x}{2}(u_x)^n_{j-1}\right)\right]\Biggr\}+{\cal O}(\lambda)$