# 1365. How Many Numbers Are Smaller Than the Current Number

## [題目:](https://leetcode.com/problems/how-many-numbers-are-smaller-than-the-current-number/)

給定一個陣列，輸出該數字在陣列中有幾個比他小的值
ex:`[8,1,2,2,3]`
輸出 `[4,0,1,1,3]`

## 思路

雙迴圈暴力解決，
比對陣列中每個數字，符合條件則count+1，在陣列中輪過一輪

func smallerNumbersThanCurrent(nums []int) []int {
	var counts []int
	for i := 0; i < len(nums); i++ {
		var count = 0
		for j := 0; j < len(nums); j++ {
			if nums[i] > nums[j] {
				count++
			}
		}
		counts = append(counts, count)

	}
	return counts
}