# LeetCode 448. Find All Numbers Disappeared in an Array [LeetCode 448. Find All Numbers Disappeared in an Array](https://leetcode.com/problems/find-all-numbers-disappeared-in-an-array/) (<font color=#00AF9B>Easy</font> 61.2%) <!-- (<font color=#00AF9B>Easy</font> 53.8%) (<font color=#FFB800>Medium</font> 39.6%) (<font color=#FF375F>Hard</font>) --> - 限制 : <ul> <li><code>n == nums.length</code></li> <li><code>1 <= n <= 10^5</code></li> <li><code>1 <= nums[i] <= n</code></li> </ul> - Solution 這題要找的是沒有在數列裡面的數是哪些。 先從頭到尾看數列裡面有哪些數,並且將有在數列裏頭的數字標記。最後再把沒有被標記的數字一一填到要回傳的數列裡面。 - 時間複雜度: $O(n)$ - 空間複雜度: $O(n)$ - 程式碼 ```c++= class Solution { public: vector<int> findDisappearedNumbers(vector<int>& nums) { vector<bool> record(nums.size(), 0); for (auto& num : nums) { record[num - 1] = true; } vector<int> result; for (int i = 0; i < record.size(); i++) { if (!record[i]) result.push_back(i + 1); } return result; } }; ``` </details>