# 8. String to Integer (atoi) https://leetcode.com/problems/string-to-integer-atoi/ ###### Medium ##### Description > Implement the myAtoi(string s) function, which converts a string to a 32-bit signed integer (similar to C/C++'s atoi function). > > The algorithm for myAtoi(string s) is as follows: > > Read in and ignore any leading whitespace. > Check if the next character (if not already at the end of the string) is '-' or '+'. Read this character in if it is either. This determines if the final result is negative or positive respectively. Assume the result is positive if neither is present. > Read in next the characters until the next non-digit charcter or the end of the input is reached. The rest of the string is ignored. > Convert these digits into an integer (i.e. "123" -> 123, "0032" -> 32). If no digits were read, then the integer is 0. Change the sign as necessary (from step 2). > If the integer is out of the 32-bit signed integer range [-231, 231 - 1], then clamp the integer so that it remains in the range. Specifically, integers less than -231 should be clamped to -231, and integers greater than 231 - 1 should be clamped to 231 - 1. > Return the integer as the final result. > Note: > > Only the space character ' ' is considered a whitespace character. > Do not ignore any characters other than the leading whitespace or the rest of the string after the digits. ##### Example > Input: str = "42" > Output: 42 > Explanation: The underlined characters are what is read in, the caret is the current reader position. > Step 1: "42" (no characters read because there is no leading whitespace) > ^ > Step 2: "42" (no characters read because there is neither a '-' nor '+') > ^ > Step 3: "42" ("42" is read in) > ^ > The parsed integer is 42. > Since 42 is in the range [-231, 231 - 1], the final result is 42. ##### Solution ```python= class Solution: def myAtoi(self, s: str) -> int: result = 0 sign = 1 start = False for c in s: if c.isdigit(): if not start: start = True result = result*10 + int(c) else: if c == ' ' and not start: continue if c == '+' and not start: start = True sign = 1 continue if c == '-' and not start: start = True sign = -1 continue break limit = result*sign if limit > 2**31 -1: limit = 2**31 -1 if limit < -2**31: limit = -2**31 return limit ```