# 7. Reverse Integer

https://leetcode.com/problems/reverse-integer/

###### Easy

##### Description
> Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.
>
> Assume the environment does not allow you to store 64-bit integers (signed or unsigned).
##### Example
> Input: x = 123
> Output: 321

##### Solution

class Solution:
    def reverse(self, x: int) -> int:

        neg = x < 0
        rev = float(0)

        if neg:
            x *= -1

        while x > 0:
            pop = x % 10
            x = int(x/10)
            rev = rev * 10 + pop

        if neg:
            rev *= -1

        if(rev > 2**31 - 1 or rev < -2**31):
            rev = 0

        return int(rev)