---
tags: DICE C
---

6-5 預算夠不夠？
===

> [name=CHAWTeam]

---

目錄：[DICE C語言程式破解](https://hackmd.io/@CHAWTeam/DiceC)
上一篇：[6-4 輸出絕對值](https://hackmd.io/@CHAWTeam/DiceC-6-4)
下一篇：[7-1 比大小](https://hackmd.io/@CHAWTeam/DiceC-7-1)

---

題目
---

小梅想要購物，她的預算只有3000元，請幫她算算想購買的商品組合，是否會超過預算？
以編號來代表商品，一次會輸入2項數字編號，請把所有商品價格相加，判斷是否超過預算，
分別輸出「符合預算」或「超出預算」。

商品有下列：

1.椅子 2300
2.書籍 800
3.帽子 500
4.櫃子 1500

因為此題輸出有多種狀況，故需將程式碼複製2次，都判斷正確才給分，每個輸出都要換行。

輸入範例1:
1 4

輸出範例1:
超出預算

輸入範例2:
2 3

輸出範例2:
符合預算

程式碼
---

#include <stdio.h>

int main()
{
    int a, b, e, f;
    scanf("%d %d", &a, &b);
    if (a == 1)
        e = 2300;
    if (a == 2)
        e = 800;
    if (a == 3)
        e = 500;
    if (a == 4)
        e = 1500;
    if (b == 1)
        f = 2300;
    if (b == 2)
        f = 800;
    if (b == 3)
        f = 500;
    if (b == 4)
        f = 1500;
    if (e + f < 3000)
        printf("符合預算\n");
    if (e + f > 3000)
        printf("超出預算\n");

    scanf("%d %d", &a, &b);
    if (a == 1)
        e = 2300;
    if (a == 2)
        e = 800;
    if (a == 3)
        e = 500;
    if (a == 4)
        e = 1500;
    if (b == 1)
        f = 2300;
    if (b == 2)
        f = 800;
    if (b == 3)
        f = 500;
    if (b == 4)
        f = 1500;
    if (e + f < 3000)
        printf("符合預算\n");
    if (e + f > 3000)
        printf("超出預算\n");
    return 0;
}

:::success
好的排版，可以讓程式碼淺顯易懂！
:::

輸出
---

1 4
超出預算
2 3
符合預算

---

[查看我們在HackMD上的所有筆記](https://hackmd.io/@CHAWTeam)
目錄：[DICE C語言程式破解](https://hackmd.io/@CHAWTeam/DiceC)
上一篇：[6-4 輸出絕對值](https://hackmd.io/@CHAWTeam/DiceC-6-4)
下一篇：[7-1 比大小](https://hackmd.io/@CHAWTeam/DiceC-7-1)

---

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---

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