---
tags: DICE C
---

10-3 逛牛墟
===

> [name=CHAWTeam]

目錄：[DICE C語言程式破解](https://hackmd.io/@CHAWTeam/DiceC)

題目
---

目前台灣僅存鹽水、善化與北港有牛墟，當然牛墟已不進行牛隻買賣的交易，而是市集的型態存在。其規則如下，
日期末位數是1, 4或7, 則牛墟在鹽水
日期末位數是2, 5或8, 則牛墟在善化
日期末位數是3, 6或9, 則牛墟在北港
日期末位數是0, 則本日沒有牛墟
超過32，則是超出範圍

請輸入日期，判斷該日的牛墟狀況，本程式可以執行4次

輸入範例:
21
20
32
15

輸出範例:
21日在鹽水
20日沒有
32日超出範圍
15日在善化

程式碼
---

#include <stdio.h>

int main()
{
    int x;
    
    scanf("%d", &x);
    if (x < 32)
    {
        if (x % 10 == 1 || x % 10 == 4 || x % 10 == 7)
            printf("%d日在鹽水\n", x);
        else if (x % 10 == 2 || x % 10 == 5 || x % 10 == 8)
            printf("%d日在善化\n", x);
        else if (x % 10 == 3 || x % 10 == 6 || x % 10 == 9)
            printf("%d日在北港\n", x);
        else if (x % 10 == 0)
            printf("%d日沒有\n", x);
    }
    else
        printf("%d日超出範圍\n", x);
    
    scanf("%d", &x);
    if (x < 32)
    {
        if (x % 10 == 1 || x % 10 == 4 || x % 10 == 7)
            printf("%d日在鹽水\n", x);
        else if (x % 10 == 2 || x % 10 == 5 || x % 10 == 8)
            printf("%d日在善化\n", x);
        else if (x % 10 == 3 || x % 10 == 6 || x % 10 == 9)
            printf("%d日在北港\n", x);
        else if (x % 10 == 0)
            printf("%d日沒有\n", x);
    }
    else
        printf("%d日超出範圍\n", x);
    
    scanf("%d", &x);
    if (x < 32)
    {
        if (x % 10 == 1 || x % 10 == 4 || x % 10 == 7)
            printf("%d日在鹽水\n", x);
        else if (x % 10 == 2 || x % 10 == 5 || x % 10 == 8)
            printf("%d日在善化\n", x);
        else if (x % 10 == 3 || x % 10 == 6 || x % 10 == 9)
            printf("%d日在北港\n", x);
        else if (x % 10 == 0)
            printf("%d日沒有\n", x);
    }
    else
        printf("%d日超出範圍\n", x);
    
    scanf("%d", &x);
    if (x < 32)
    {
        if (x % 10 == 1 || x % 10 == 4 || x % 10 == 7)
            printf("%d日在鹽水\n", x);
        else if (x % 10 == 2 || x % 10 == 5 || x % 10 == 8)
            printf("%d日在善化\n", x);
        else if (x % 10 == 3 || x % 10 == 6 || x % 10 == 9)
            printf("%d日在北港\n", x);
        else if (x % 10 == 0)
            printf("%d日沒有\n", x);
    }
    else
        printf("%d日超出範圍\n", x);
    
    return 0;
}

輸出
---

21
20
32
15
21日在鹽水
20日沒有
32日超出範圍
15日在善化

---

[查看我們在HackMD上的所有筆記](https://hackmd.io/@CHAWTeam)
目錄：[DICE C語言程式破解](https://hackmd.io/@CHAWTeam/DiceC)

---

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