# (Easy) 169. Majority Element ## Run Code  ## 題意 在名為nums的arrray中,找出當中出現最多次的那一個。 ## 解題思路 就找出最多的那一個OWO ## 困難之處 沒甚麼困難的,差別只有Big O 的問題。 (p.s)下面還有提供一個O(n)的code。 ## Code ```cpp= class Solution { public: int majorityElement(vector<int>& nums) { std::map<int,int> number; for(std::vector<int>::iterator it=nums.begin();it!=nums.end();it++) number[*it]++; std::map<int,int>::iterator answer=number.begin(); for(std::map<int,int>::iterator it=number.begin();it!=number.end();it++) if(it->second > answer->second) answer = it; return answer->first; } }; ``` ## Code with O(n) ```cpp= class Solution { public: int majorityElement(vector<int>& nums) { int major=nums[0], count=1; for(int i=1;i<nums.size();i++){ if(count==0){ count++; major = nums[i]; } else if(major==nums[i]) count++; else count--; } return major; } }; ``` ###### tags: `leetcode`
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