# 442. Find All Duplicates in an Array ## 題目敘述  題目意思: ## 初步想法 ### 第一次看到 新建一個Object、array去統計每個數字出現次數,比如 1. Input: nums = [4,3,2,7,8,2,3,1],輸出{1:1,2:2,3:2,4:1...} 2. 當nums.value>1,將nums.key放入output中輸出 ## 解題 ### 作法1 : Array、Object ``` var findDuplicates = function(nums) { let outP = [] let keys ={} for(let i in nums){ if(keys[nums[i]] == undefined){ keys[nums[i]] = 1 } else{ keys[nums[i]] += 1 if(keys[nums[i]] > 1) outP.push(nums[i]) } } return outP }; ``` ### 最終結果  ### 作法2 : Array ``` var findDuplicates = function(nums) { let outP = [] let key = [] for(let i in nums){ if(key[nums[i]-1] === undefined) key[nums[i]-1] = 1 else key[nums[i]-1]++ if(key[nums[i]-1] > 1) outP.push(nums[i]) } return outP }; ``` ### 最終結果  ### 作法3: abs() ### 作法4:大風吹 ###### tags: `Leetcode`
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