# LC 2660. Determine the Winner of a Bowling Game

### [Problem link](https://leetcode.com/problems/determine-the-winner-of-a-bowling-game/)

###### tags: `leedcode` `easy` `python`

You are given two **0-indexed** integer arrays <code><font face="monospace">player1</font></code> and <code>player2</code>, that represent the number of pins that player 1 and player 2 hit in a bowling game, respectively.

The bowling game consists of <code>n</code> turns, and the number of pins in each turn is exactly <code>10</code>.

Assume a player hit <code>x_i</code> pins in the <code>i^th</code> turn. The value of the <code>i^th</code> turn for the player is:

- <code>2x_i</code> if the player hit <code>10</code> pins in any of the previous two turns.
- Otherwise, It is <code>x_i</code>.

The score of the player is the sum of the values of their <code>n</code> turns.

Return

- <code>1</code> if the score of player 1 is more than the score of player 2,
- <code>2</code> if the score of player 2 is more than the score of player 1, and
- <code>0</code> in case of a draw.

**Example 1:**

Input: player1 = [4,10,7,9], player2 = [6,5,2,3]
Output: 1
Explanation: The score of player1 is 4 + 10 + 2*7 + 2*9 = 46.
The score of player2 is 6 + 5 + 2 + 3 = 16.
Score of player1 is more than the score of player2, so, player1 is the winner, and the answer is 1.

**Example 2:**

Input: player1 = [3,5,7,6], player2 = [8,10,10,2]
Output: 2
Explanation: The score of player1 is 3 + 5 + 7 + 6 = 21.
The score of player2 is 8 + 10 + 2*10 + 2*2 = 42.
Score of player2 is more than the score of player1, so, player2 is the winner, and the answer is 2.

**Example 3:**

Input: player1 = [2,3], player2 = [4,1]
Output: 0
Explanation: The score of player1 is 2 + 3 = 5
The score of player2 is 4 + 1 = 5
The score of player1 equals to the score of player2, so, there is a draw, and the answer is 0.

**Constraints:**

- <code>n == player1.length == player2.length</code>
- <code>1 <= n <= 1000</code>
- <code>0 <= player1[i], player2[i] <= 10</code>

## Solution 1
#### Python

class Solution:
    def isWinner(self, player1: List[int], player2: List[int]) -> int:
        res = 0

        def calScore(scores):
            bonus = 0
            
            if len(scores) >= 2 and scores[0] == 10:
                bonus += scores[1]
            
            for i in range(2, len(scores)):
                if scores[i - 1] == 10 or scores[i - 2] == 10:
                    bonus += scores[i]
                    
            return sum(scores) + bonus
                    
        s1 = calScore(player1)
        s2 = calScore(player2)
        
        if s1 > s2:
            res = 1
        elif s1 < s2:
            res = 2
        else:
            res = 0

        return res
            

>### Complexity
>n = player1.length = player2.length
>| | Time Complexity | Space Complexity |
>| ----------- | --------------- | ---------------- |
>| Solution 1 | O(n) | O(1) |

## Note
x