# LC 3201. Find the Maximum Length of Valid Subsequence I ### [Problem link](https://leetcode.com/problems/find-the-maximum-length-of-valid-subsequence-i/) ###### tags: `leedcode` `medium` `c++` `DP` You are given an integer array <code>nums</code>. A <span data-keyword="subsequence-array">subsequence <code>sub</code> of <code>nums</code> with length <code>x</code> is called **valid** if it satisfies: - <code>(sub[0] + sub[1]) % 2 == (sub[1] + sub[2]) % 2 == ... == (sub[x - 2] + sub[x - 1]) % 2.</code> Return the length of the **longest** **valid** subsequence of <code>nums</code>. A **subsequence** is an array that can be derived from another array by deleting some or no elements without changing the order of the remaining elements. **Example 1:** <div class="example-block"> Input: <span class="example-io">nums = [1,2,3,4] Output: <span class="example-io">4 Explanation: The longest valid subsequence is <code>[1, 2, 3, 4]</code>. **Example 2:** <div class="example-block"> Input: <span class="example-io">nums = [1,2,1,1,2,1,2] Output: 6 Explanation: The longest valid subsequence is <code>[1, 2, 1, 2, 1, 2]</code>. **Example 3:** <div class="example-block"> Input: <span class="example-io">nums = [1,3] Output: <span class="example-io">2 Explanation: The longest valid subsequence is <code>[1, 3]</code>. **Constraints:** - <code>2 <= nums.length <= 2 * 10<sup>5</sup></code> - <code>1 <= nums[i] <= 10<sup>7</sup></code> ## Solution 1 - DP #### C++ ```cpp= class Solution { public: int maximumLength(vector<int>& nums) { vector<vector<int>> dp(2, vector<int>(2, 0)); int ans = 0; for (int num: nums) { num %= 2; for (int i = 0; i < 2; i++) { dp[i][num] = dp[num][i] + 1; ans = max(ans, dp[i][num]); } } return ans; } }; ``` >### Complexity >| | Time Complexity | Space Complexity | >| ----------- | --------------- | ---------------- | >| Solution 1 | O(k^2 + nk) | O(k^2) | ## Note 套用[LC 3202. Find the Maximum Length of Valid Subsequence II](https://hackmd.io/@Alone0506/rJMvMJ1PR)的作法