### 學習繪製流程圖 -- 以判斷閏年、平年為例

st=>start: 開始
ed=>end: 結束
mg0=>operation: msg = "是閏年"
mg1=>operation: msg = "是平年"
io0=>inputoutput: 給定一個正整數yr
op0=>operation: msg = yr.toString() + msg
cond=>condition: yr為偶數?
cond1=>condition: yr可以被4整除?
cond2=>condition: yr可以被100整除?
cond3=>condition: yr可以被400整除?

st->io0->cond

cond(no)->mg1
cond(yes)->cond1

cond1(yes)->cond2
cond1(no)->mg1

cond2(no)->mg0
cond2(yes)->cond3

cond3(no)->mg1
cond3(yes)->mg0

mg1->op0
mg0->op0
op0->ed

### CSMA/CD 流程圖

st=>start: 開始
ed0=>end: 送出成功
ed1=>end: 放棄傳送
temp=>operation: CSMA/CD
op0=>operation: 延遲一段時間
op1=>operation: 延遲9.6us送出資料框
op2=>operation: 算出隨機等待時間
op3=>operation: 等待一段隨機時間
cond0=>condition: 網路有空?
cond1=>condition: 發生碰撞?
cond2=>condition: 未達15次?

st->temp->cond0

cond0(no)->op0(top)->temp
cond0(yes)->op1->cond1

cond1(yes)->cond2
cond1(no)->ed0

cond2(yes)->op2->op3
cond2(no)->ed1

op3(bottom)->temp

# 台中市計程車費率

st=>start: 開始
ed=>end: 結束
io=>inputoutput: 搭乘里程D(公尺)
ot=>inputoutput: 車資費用(元)F = 85 + C * 5
ot1=>inputoutput: 車資85元
cond1=>condition: D >= 1500?
cond2=>condition: M <> 0?
op2=>operation: M = 取餘數( (D - 1500) / 200 )
op3=>operation: 跳錶次數C = 無條件進位( (D - 1500) / 200 ) +1 
op4=>operation: 跳錶次數C = 無條件進位( (D - 1500) / 200 )

st->io->cond1

cond1(no)->ot1->ed
cond1(yes)->op2

op2->cond2

cond2(no)->op3
cond2(yes)->op4

op3->ot
op4->ot

ot->ed

# 傅里德曼方程式
$$
H^2 = \Big( {\dot{a} \over a} \Big)^2 = {8 \pi G \over 3}\rho - {kc^2 \over a^2} + {\Lambda c^2 \over 3}
$$

$$
x = \Big( {{-b \pm \sqrt{b^2 -4ac}} \over2a} \Big)
$$

$$
\sum_{i=1}^{100} i = {1 + 2 + 3 + ... + 100} = 5050
$$